【头歌-Python】Python第六章作业

慈云数据 2024-05-30 技术支持 48 0

第1关:列表的属性与方法

a = int(input())
ls = []
for i in range(a):
    t = input().split(" ")
    if t[0] == 'iNSErt':
        ls.insert(int(t[1]), int(t[2]))
    elif t[0] == 'print':
        print(ls)
    elif t[0] == 'remove':
        ls.remove(int(t[1]))  
    elif t[0] == 'append':
        ls.append(int(t[1]))
    elif t[0] == 'sort':
        ls.sort()
    elif t[0] == 'pop':
        ls.pop()
    elif t[0] == 'reverse':
        ls.reverse()

第2关:推导式与生成器

ls = ['the lord of the rings', 'anaconda', 'legally blonde', 'gone with the wind']
s = input()  
if s == '1':
    print([x ** 3 for x in range(10)])
elif s == '2':
    print([x ** 3 for x in [0, 2, 4, 6, 8]])
elif s == '3':
    print([(x, x ** 3) for x in [1, 3, 5, 7, 9]])
elif s == '4':
    for i in range(4):
        ls[i] = ls[i].cAPItalize()
    print(ls)
else:
    print('结束程序')

第3关:列表的合并排序

list1 = list(map(int,input().split()))
list2 = list(map(int,input().split()))
for i in list2:
    list1.append(i)
list1.sort(reverse=True)
print(list1)

第4关:二维列表排序

a = int(input())
b = int(input())
list1 = [('dungeon',7),('winterfell',4),('bran',9),('meelo',6)]
list2 = [[ 'Angle', '0121701100106',99], [ 'Jack', '0121701100107',86], [ 'Tom', '0121701100109',65], [ 'Smith', '0121701100111', 100], ['Bob', '0121701100115',77], ['Lily', '0121701100117', 59]]
if a>=len(list1):
    print(sorted(list1,key = lambda x:x[1]))
else:
    print(sorted(list1,key = lambda x:x[1])[0:a])
if b>=len(list2):
    print(sorted(list2,key = lambda x:x[0]))
    print(sorted(list2,key = lambda x:x[2]))
else:
    print(sorted(list2,key = lambda x:x[0])[0:b])
    print(sorted(list2,key = lambda x:x[2])[0:b])

第5关:动物重量排序

ls = []
while True:
    temp = input() 
    if temp == '': 
        break
    ls.append(temp.split()) 
print(sorted(ls,key=lambda x:float(x[1][:-1]) * 1000 if x[1][-1] == 't' else float(x[1][:-2])))

第6关:身份证号升位

a = input()
if (int(a[6]) == 0 and int(a[7]) >= 5) or int(a[6]) > 0:
    str = a[:6] + '19' + a[6:]
else:
    str = a[:6] + '20' + a[6:]
sum = (int(str[0]) * 7 + int(str[1]) * 9 + int(str[2]) * 10 + int(str[3]) * 5 + int(str[4]) * 8 + int(str[5]) * 4 + int(str[6]) * 2 + int(str[7]) * 1 + int(str[8]) * 6 + int(str[9]) * 3 + int(str[10]) * 7 + int(str[11]) * 9 + int(str[12]) * 10 + int(str[13]) * 5 + int(str[14]) * 8 + int(str[15]) * 4 + int(str[16]) * 2) % 11
if sum == 0:
    str = str + '1'
if sum == 1:
    str = str + '10'
if sum == 2:
    str = str + 'X'
if sum == 3:
    str = str + '9'
if sum == 4:
    str = str + '8'
if sum == 5:
    str = str + '7'
if sum == 6:
    str = str + '6'
if sum == 7:
    str = str + '5'
if sum == 8:
    str = str + '4'
if sum == 9:
    str = str + '3'
if sum == 10:
    str = str + '2'
print(str)

第7关:完美立方数

Cube = int(input())
for i in range(2,Cube+1):
    for a in range(2,i+1):
        for b in range(a,i+1):
            for c in range(b,i+1):
                if pow(i,3)==pow(a,3)+pow(b,3)+pow(c,3):
                    print('Cube = {},Triple = ({},{},{})'.format(i,a,b,c))
           

第8关:约瑟夫环问题

n, k = map(int, input().split(' '))
ls = []
if k 
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